5x^2+28=-27x

Solution for 5x^2+28=-27x equation:

5x^2+28=-27x

We move all terms to the left:

5x^2+28-(-27x)=0

We get rid of parentheses

5x^2+27x+28=0

a = 5; b = 27; c = +28;
Δ = b2-4ac
Δ = 272-4·5·28
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-13}{2*5}=\frac{-40}{10}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+13}{2*5}=\frac{-14}{10}
=-1+2/5
$